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The C++23 added a new use case for the auto keyword. auto can now produce a prvalue copy of an argument.

auto(arg) being equivalent to T(arg) and auto{arg} being equivalent to T{arg}, with the benefit that we do not have to get access to T (using T = std::decay_t<decltype(arg)>;).

Due to C++17 direct initialization, auto will never produce excessive copies.

Compiler Explorer link: https://compiler-explorer.com/z/Gq8xEjj58